Q1 of 104 Page 196

Evaluate:

cos(90–θ ) = sinθ

tan(90–θ ) = cotθ


sin(90–θ ) = cosθ


cot(90–θ ) = tanθ


cosec(90–θ ) = secθ


sec(90–θ) = cosecθ






More from this chapter

All 104 →
1

Evaluate:

cot12 ⋅ cot38 ⋅ cot52 ⋅ cot60 ⋅ cot78

 1

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+ √3 (tan10 tan30 tcm40 tan50 tan80–

 2

Prove the following:

sin48 sec42 + cos48 cosec42 = 2

 2

Prove the following:

— 2cos70 cosec20 = 0