In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5,06,000.
Initial count (P) = 5,06,000
Rate of increase (R) = 2.5% per hour
No. of hours(n) = 2
The count of bacteria after 2 hours = ![]()
= ![]()
= 5060 × 102.52
= 5,31,61,625
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