Let us find the median of given data.

The data given in the question is exclusive type of data.

To find median of data, we need to make a table calculating cumulative frequency.

For median:

We have, total frequency, N = 622

N/2 = 622/2 = 311

Observe, cf = 391 is just greater than 311.

Thus, median class = 60 – 70

Median is given by

Where,

L = Lower class limit of median class = 60

N/2 = 311

cf = cumulative frequency of the class preceding median class = 289

f = frequency of the median class = 102

h = class interval of the median class = 10

Substituting these values in the formula of median, we get

⇒

⇒ Median = 60 + 2.157

⇒ Median = 62.157

Thus, the median of data is 62.157.