Q10 of 55 Page 364

The following frequency distribution shows the time taken to complete 100 metre hardle race of 150 athletics :


Let us find the difference between the upper class limit of modal class and lower class limit of modal class.

To find modal class, find the greatest frequency.

⇒ Greatest frequency = 71


So, corresponding to this value of frequency, we get class = 14.2 – 14.6


⇒ Modal class = 14.2 – 14.6


So, upper class limit of modal class = 14.6


Lower class limit of modal class = 14.2


Difference = Upper class limit of modal class – Lower class limit of modal class


⇒ Difference = 14.6 – 14.2


⇒ Difference = 0.4


Thus, difference is 0.4.


More from this chapter

All 55 →
9

Let us fill in the blanks :

i. Mean, median, mode are measures of ________.


ii. If mean of x1,x2,x3……..xn is mean of ax1,ax2,ax3……..axn is _________.


iii. At the time of finding arithmetic mean, the lengths of all classes are _______.

 10

Short answer type question :


Let us find the difference between upper class limit in median class and lower class limit of modal class of the above frequency distribution table.

 10

The mean of frequency distribution is 8.1, and let us find the value of k.

 10

If and let us find the value of


Let us write the modal class from the above frequency distribution table.