If tan2 a – tan2 b. Prove that:
.
Formula: -
(i) tan2x = sec2x – 1
(ii) cos2x = 1 – sin2x
Taking L.H.S and applying formula (i) we get,
tan2A – tan2B = sec2A – 1 – (sec2B – 1)
⇒ tan2A – tan2B = sec2A – 1 – sec2B + 1
⇒ tan2A – tan2B = sec2A – sec2B
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Applying formula (ii) we get,
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L.H.S = R.H.S
Hence, Proved.
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