If a cos 3θ + 3 sin2θ cosθ = m and sin3θ + 3 a sinθ cos2θ = n then prove that:
.
Given:
a cos 3θ + 3 sin2 θ cos θ = m
sin 3θ + 3 a sin θ cos 2θ = n
Now adding both the equations we get,
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Adding (i) and (ii) we get,
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Hence, Proved.
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