Q2 of 25 Page 130

A man throws a ball of mass 0.5 kg vertically upward with a velocity of 25 m / s. Find the initial momentum of the ball and momentum of the ball at the Halfway mark of the maximum height.

Initial velocity = u = 25m/s

Final velocity at highest point = v = 0m/s


Using 3rd equation of motion;


v2 = u2 + 2gs


02 = (25)2 – 2(9.8)s


0 = 625 – 19.6s


31.8m = s


So, half distance = 15.9m


Velocity at halfway = ?


Using the 3rd equation of motion


v2 = u2 – 2gs


v2 = (25)2 – 2(9.8)(15.9)


v2 = 625 – 311.64


v = √313.36


v = 17.7m/s


Initial momentum = mu


= (0.5)(25)


= 12.5kgm/s


Momentum at halfway = mv


= (0.5)(17.7)


= 8.85kgm/s


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