Q11 of 25 Page 130

A car accelerates from rest at a constant rate for t seconds and covers a distance x. The distance covered by it in next t second will be?

Initial velocity = u = 0m/s

Time = t s


Distance = x m


According to Second equation of motion


s = ut + 1/2 at2


x = 0 + 1/2 at2



According to the first equation of motion


v = u + at




Now for next t sec



According to Second equation of motion


s = ut + 1/2 at2



s = 2x + x


s = 3x


∴ the distance covered in the next “t” second will be 3x.


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