Q5 of 35 Page 55

A particle is thrown upwards. It attains a height h after 5 s and again after 9s comes back. What is the speed of the particle at a height h?

Given,

Total time taken by particle to reach initial position = T’



Now, we know tithe me of ascent = Time of descent = T



Given,


At t = 5 s particle is at a height h


Now t = 5s is the time that comes in descending.


So the time taken by the particle to reach h


Let v be the speed of pthe article at h






Hence the speed of the particle at h height is


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