Q33 of 35 Page 55

A particle covers 10m in first 5 s and 10m in next 3 s assuming constant acceleration. Find initial speed acceleration and distance covered in next 2 s.

Distance covered in first 5 seconds = 10 m ..1

Distance covered in next 3 seconds = 10 m ..2


So, distance covered in 8 seconds = 10 + 10 = 20 m..3


Now, let initial speed = u and acceleration = a


Now, using equations of motion:


..4



Solving 5 and 6, we get:



Now, initial speed = u =


And acceleration = a =


So, to find distance covered in the next 2 seconds


Distance covered in next 2 s = (Distance covered in 10 s – Distance covered in 8 s)


Now, t = 10 s;


So, using equation 4, we get:





So, distance travelled in next 2 s = (28.33 – 20)


= 8.33 m


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