A body travels half of its total path in the last second of its free fall from rest. The duration of the fall is nearly?
Since this is a free fall:
u = 0 and a = g = 9.8 ms–2
Let the total time of free fall be T, and total distance travelled be H.
We use the second equation of motion:
..1
Given:
A body travels half of its total path in last second. This also means that the body travels half of its total path in (T – 1) s.
Now, using 1:
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..2
Also, ![]()
..3
Equating 2 and 3, we get:
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