A body travels a distance of 2 m in 2 s and 2.2 m in next 4 s. What will be the velocity of the body at the end of 7th second from the start?
Given: Distance travelled in 2 s = 2 m
Distance travelled in next 4 s = 2.2 m
To Find: Velocity at the end of 7th second
Equations Used:
..1
..2
..3
Where v = Final Velocity t = Time
u = Initial Velocity s = Distance
a = Acceleration
Case – 1: First two seconds
t = 2 s; s = 2m;
So, using 2;
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..4
Case – 2: Motion in next 4 s
Now, Distance travelled = 2.2 m
Total distance in 6 s is given by = 2 + 2.2 = 4.2 m
So, s = 4.2 m and t = 6 s
Now, using 2:
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..5
Solving 4 and 5, we get:
And ![]()
So, velocity after 7 seconds:
; ![]()
Using equation 1:
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Hence velocity at the end of the 7th second is
.
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