A person goes to his office from his home daily at a fixed speed. But today he decided to reduce his speed by 20%. As a result he reaches his office 16 minutes late. What's the actual time he takes to reach his office daily?
Let v be the fixed speed of the person and t be the actual time taken to reach office.
Now, Distance to Office = Speed × Time = vt
Now, the speed is decreased by 20%
So, New Speed = v – 0.2 × v
= v
= ![]()
And hence the new time taken is given by:
New Time Taken = t + 16
So, distance to office =
× (t + 16)
Now, we know that distance to office is always fixed.
So,
× (t + 16) = vt
= t
4t + 64 = 5t
t = 64 s
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.