Q68 of 354 Page 11

If prove that .

Given


We have 1 + cos(2θ) = 2cos2θ and 1 + cos(2θ) = 2sin2θ.





[∵ log(am) = m × log(a)]



On differentiating y with respect to x, we get



We know


[using chain rule]


However,







We have sin(2θ) = 2sinθcosθ





Thus,


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