Differentiate
with respect to
if –1 < x < 1.
Let
and
.
We need to differentiate u with respect to v that is find
.
We have ![]()
By substituting x = tan θ, we have
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[∵ sec2θ – tan2θ = 1]

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⇒ u = sin–1(2sinθcosθ)
But, sin2θ = 2sinθcosθ
⇒ u = sin–1(sin2θ)
Given –1 < x < 1 ⇒ x ϵ (–1, 1)
However, x = tan θ
⇒ tan θ ϵ (–1, 1)
![]()
![]()
Hence, u = sin–1(sin2θ) = 2θ
⇒ u = 2tan–1x
On differentiating u with respect to x, we get
![]()
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We know![]()
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Now, we have ![]()
By substituting x = tan θ, we have
![]()
![]()
But, ![]()
⇒ v = tan–1(tan2θ)
However, ![]()
Hence, v = tan–1(tan2θ) = 2θ
⇒ v = 2tan–1x
On differentiating v with respect to x, we get
![]()
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We know![]()
![]()
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We have 

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Thus, ![]()
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