If xmyn = 1, prove that

Q39 of 354 Page 12

If x^myⁿ = 1, prove that

Here,

Taking log on both sides,

log() = log 1

m logx + n logy=log 1 [ Since, log (AB)=logA+logB ; log =b log a]

Differentiating with respect to x

Hence Proved.

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