Differentiate
with respect to
if 0 < x < 1.
Let
and ![]()
We need to differentiate u with respect to v that is find
.
We have ![]()
By substituting x = cos θ, we have
![]()
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[∵ sin2θ + cos2θ = 1]
⇒ u = sin–1(sinθ)
Given, 0 < x < 1 ⇒ x ϵ (0, 1)
However, x = cos θ
⇒ cos θ ϵ (0, 1)
![]()
Hence, u = sin–1(sinθ) = θ
⇒ u = cos–1x
On differentiating u with respect to x, we get
![]()
We know![]()
![]()
Now, we have ![]()
By substituting x = cos θ, we have

![]()
[∵ sin2θ + cos2θ = 1]
![]()
⇒ v = cot–1(cotθ)
However, ![]()
Hence, v = cot–1(cotθ) = θ
⇒ v = cos–1x
On differentiating v with respect to x, we get
![]()
We know![]()
![]()
We have 


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Thus, ![]()
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