Differentiate
with respect to
if 0 < x < 1.
Let
and
.
We need to differentiate u with respect to v that is find
.
We have ![]()
By substituting x = tan θ, we have
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But, ![]()
⇒ u = tan–1(tan2θ)
Given 0 < x < 1 ⇒ x ϵ (0, 1)
However, x = tan θ
⇒ tan θ ϵ (0, 1)
![]()
![]()
Hence, u = tan–1(tan2θ) = 2θ
⇒ u = 2tan–1x
On differentiating u with respect to x, we get
![]()
![]()
We know![]()
![]()
![]()
Now, we have ![]()
By substituting x = tan θ, we have


[∵ sec2θ – tan2θ = 1]


⇒ v = cos–1(cos2θ – sin2θ)
But, cos2θ = cos2θ – sin2θ
⇒ v = cos–1(cos2θ)
However, ![]()
Hence, v = cos–1(cos2θ) = 2θ
⇒ v = 2tan–1x
On differentiating v with respect to x, we get
![]()
![]()
We know![]()
![]()
![]()
We have 

![]()
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Thus, ![]()
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