Q8 of 104 Page 1

Find the LCM and HCF of the following pair of integers and verify that LCM X HCF = Product of two numbers :

96 and 404

Given numbers are 96 and 404


The prime factorization of 96 and 404 gives:


96 = 25 × 3 and 404 = 22 × 101


Therefore, the H.C.F of these two integers = 22 = 4


Now, the L.C.M of 96 and 404 = 2 × 2 × 2 × 2 × 2 × 3 × 101 = 9696


Now, we have to verify



L.H.S = L.C.M × H.C.F = 9696 × 4 = 38784


R.H.S = Product of two numbers = 96 × 404 = 38784


Hence, L.H.S = R.H.S


So, the product of two numbers is equal to the product of their HCF and LCM.


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