Prove that following numbers are irrational :
3 + √5
Let us assume 3 +
is rational
3 +
can be written in the form
where a and b are co-prime.
Hence, 3 +
= ![]()
=
– 3
= ![]()
= ![]()

Since, rational ≠ irrational
This is a contradiction.
, Our assumption is incorrect.
Hence, 3 +
is irrational.
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