Q10 of 104 Page 1

If LCM (72, 126) = 504, find HCF (72, 126)

Given: LCM (72, 126) = 504


To Find: HCF (72, 126)


We use the formula


L.C.M (a,b) × H.C.F (a,b) = Product of two numbers (a×b)


LCM (72, 126) × HCF (72, 126) = 72 × 126


⇒ 504 × HCF (72, 126) = 72 × 126 [LCM(72,126)=504]


⇒ HCF (72, 126) =


⇒ HCF (72 , 126) = 18


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