Prove that following numbers are not rational :
3√3
Let us assume that 3
be a rational number.
Then, it will be of the form
where a and b are co-prime and b≠0.
Now,
=3![]()
=![]()
Since, a is an integer and 3b is also an integer (3b ≠ 0)
So,
is a rational number
is a rational number
But this contradicts to the fact that
is an irrational number.
Therefore, our assumption is wrong.
Hence, 3
is an irrational number.
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