Find the length of the tangent drawn from a point, whose distance from the centre of a circle is 5c, and the radius of the circle is 3 cm.
Let A be the point at distance of 5 cm from the centre as AO = 5 cm
AB is the tangent at point B as shown
OB is the radius which is 3 cm

Now we know that radius is perpendicular to point of contact
Hence OB is perpendicular to AB
Hence ∠ABO = 90°
Consider ΔABO
Using Pythagoras theorem
⇒ AB2 + OB2 = AO2
⇒ AB2 + 32 = 52
⇒ AB2 + 9 = 25
⇒ AB2 = 25 – 9
⇒ AB2 = 16
⇒ AB = ±4
As length cannot be negative
⇒ AB = 4 cm
Hence length of tangent is 4 cm
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