In the given figure, two radii OP and OQ of a circle are mutually perpendicular. What is the degree measure of the angle between tangents drawn to the circle at P and Q?

a) we have to find ∠PTQ which is the angle between the tangents TP and TQ
∠OPT = ∠OQT = 90° …radius is perpendicular to tangent at point of contact
∠POQ = 90° …given
Consider quadrilateral POQT
⇒ ∠OPT + ∠OQT + ∠POQ + ∠PTQ = 360° …sum of angles of quadrilateral
⇒ 90° + 90° + 90° + ∠PTQ = 360°
⇒ 270° + ∠PTQ = 360°
⇒ ∠PTQ = 90°
Hence angle between tangents is 90°
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