From a point P, the length of the tangent to a circle is 15 cm, and the distance of P from the centre of the circle is 17cm. Then what is the radius of the circle?
Let the centre of circle be O so that PO = 17 cm
Tangent is PB whose length is 15 cm
OB is radius as shown

Now we know that radius is perpendicular to point of contact
Hence OB is perpendicular to PB
Hence ∠PBO = 90°
Consider ΔPBO
Using Pythagoras theorem
⇒ PB2 + OB2 = PO2
⇒ 152 + OB2 = 172
⇒ OB2 = 172 - 152
⇒ OB2 = 289 – 225
⇒ OB2 = 64
⇒ OB = ±8
As length cannot be negative
⇒ OB = 8 cm
Hence length of radius is 8 cm
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