Q9 of 35 Page 11

In the given figure, a measure of ∠POQ is…..

PQ is tangent to circle and OP is radius


⇒ ∠OPQ= 90° …radius is perpendicular to tangent


⇒ ∠PQO = 30° …given


Consider ΔOPQ


⇒ ∠OPQ + ∠PQO + ∠POQ = 180° …sum of angles of triangle


⇒ 90° + 30° + ∠POQ = 180°


⇒ 120° + ∠POQ = 180°


⇒ ∠POQ = 60°


Hence ∠POQ is 60°


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