Q2 of 44 Page 14

A solid is in the form of a right circular cone mounted on a hemisphere. The radius of the hemisphere is 2.1 cm, and the height of the cone is 4 cm. The solid is place in a cylindrical tub full of water in such a way that the whole solid is submerged in water left in the tub.

Original volume of water in the cylindrical tub

= Volume of Cylinder


= πr2h



= 22×25×1.4


= 770cm3


Given that Radius of hemisphere, R = 2.1cm


and height of cone, h = 4cm


Volume of a solid = Volume of cone + Volume of hemisphere






= 37.884cm3


∴ Volume of water displaced (removed) = 37.884cm3


Hence, the required volume of the water left in the cylindrical tub = 770 – 37.884


= 732.116 cm3


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