Q15 of 44 Page 14

A solid iron pole is having a cylindrical portion 110 cm high and of base diameter, 12 cm is surmounted by a cone 9 cm high. Find the mass of the pole, given that mass of 1 cm3 of iron is 8 g.


Given: Diameter of cone = 12cm


So, Radius of cone = 6cm


and Height of cone = 9cm




= 339.428 cm3


Radius of the cylinder, R = Radius of cone = 6cm


Height of the cylinder, H = 110cm


Volume of cylinder = πR2H



= 12445.714cm3


Hence, the volume of the pole


= Volume of conical part + Volume of the cylindrical part


= 339.43 + 12445.714


= 12785.142 cm3


Required mass of pole = 8 × 12785.142


= 102281.13 gm


= 102.281kg


More from this chapter

All 44 →