A solid iron pole is having a cylindrical portion 110 cm high and of base diameter, 12 cm is surmounted by a cone 9 cm high. Find the mass of the pole, given that mass of 1 cm3 of iron is 8 g.

Given: Diameter of cone = 12cm
So, Radius of cone = 6cm
and Height of cone = 9cm
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= 339.428 cm3
Radius of the cylinder, R = Radius of cone = 6cm
Height of the cylinder, H = 110cm
Volume of cylinder = πR2H
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= 12445.714cm3
Hence, the volume of the pole
= Volume of conical part + Volume of the cylindrical part
= 339.43 + 12445.714
= 12785.142 cm3
Required mass of pole = 8 × 12785.142
= 102281.13 gm
= 102.281kg
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