A metal cube of edge 12 cm is melted and formed into three smaller cubes. If the edges of two smaller cubes are 6 cm and 8 cm, find the edge of the third smaller cube (Assume that there is no loss of metal during melting)
Let the edge of the third smaller cube be x cm.
Three small cubes are formed by melting the cube of edge 12 cm.
Edges of two small cubes are 6 cm and 8 cm.
Now, volume of a cube = (side)3
Volume of the big cube = sum of the volumes of the three small cubes
⇒ (12)3 = (6)3 + (8)3 + (x)
⇒ 1728 = 216 + 512 + x3
⇒ 1728 = 728 + x3
⇒ x3 = 1728 – 728
⇒ x3 = 1000
⇒ x = 10 cm
Therefore, the edge of the third cube is 10 cm
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