A solid sphere of radius 6cm is melted into a hollow cylinder of uniform thickness. If the external radius of the base of the cylinder is 5cm and its height is 32 cm, find the uniform thickness of the cylinder.
Let inner radius of the cylinder be x cm
Given that radius of sphere = 6cm
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= ![]()
= 4 × π × 2 × 36 cm3
It is also given that external radius of base of cylinder (R) = 5cm
and height = 32cm
∴ Volume of hollow cylinder = πh[R2 – r2]
= π × 32 × [(5)2 – x2]
= 32π [25 – x2]
Solid sphere is melted and casted into hollow cylinder
∴ Volume of sphere = Volume of hollow cylinder
⇒ 4 × π × 2 × 36 = 32π [25 – x2]
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⇒ 9 – 25 = -x2
⇒ x2 = 16
⇒ x = ±4
⇒ x = 4cm
Hence, the inner radius of the cylinder is 4cm
So, the thickness of the cylinder = external radius – inner radius
= 5 – 4
= 1cm
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