Differentiate the following from first principle.
eax + b
We need to find derivative of f(x) = eax + b
Derivative of a function f(x) is given by –
f’(x) =
{where h is a very small positive number}
∴ derivative of f(x) = eax + b is given as –
f’(x) = ![]()
⇒ f’(x) = ![]()
⇒ f’(x) = ![]()
Taking eax + b common, we have –
⇒ f’(x) = ![]()
Using algebra of limits –
⇒ f’(x) = ![]()
As one of the limits
can’t be evaluated by directly putting the value of h as it will take 0/0 form.
So we need to take steps to find its value.
⇒ f’(x) = ![]()
Use the formula: ![]()
⇒ f’(x) = eax + b × (a)
⇒ f’(x) = aeax + b
Hence,
Derivative of f(x) = eax + b = aeax + b
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