Write the value of the derivation of f(x) = |x – 1| + |x – 3| at x = 2.
As we need to differentiate f(x) = |x – 3| + |x – 1|
We know the property of a mod function that–
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∴ 
∴ 
Hence,

As ![]()
∴ 
From above equation, we can say that
value of derivative at x = 2 is 0 ⇒ f’(2) = 0
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