Differentiate the following from first principles
![]()
We need to find derivative of f(x) = ![]()
Derivative of a function f(x) from first principle is given by –
f’(x) =
{where h is a very small positive number}
∴ derivative of f(x) =
is given as –
f’(x) = ![]()
⇒ f’(x) = ![]()
⇒ f’(x) = 
⇒ f’(x) = ![]()
Use the formula: sin (A – B) = sin A cos B – cos A sin B
⇒ f’(x) = ![]()
Using algebra of limits, we have –
⇒ f’(x) = ![]()
⇒ f’(x) = ![]()
⇒ f’(x) = ![]()
⇒ f’(x) = ![]()
As, h → 0 ⇒
→ 0
∴ To use the sandwich theorem to evaluate the limit, we need
in denominator. So multiplying this in numerator and denominator.
⇒ f’(x) = ![]()
Using algebra of limits –
⇒ f’(x) = ![]()
Use the formula: ![]()
∴ f’(x) =
× 1 ×![]()
⇒ f’(x) = ![]()
Again, we get an indeterminate form, so multiplying and dividing √(x + h) + √(x) to get rid of indeterminate form.
∴ f’(x) = ![]()
Using a2 – b2 = (a + b)(a – b), we have –
⇒ f’(x) = ![]()
Using algebra of limits we have –
⇒ f’(x) = ![]()
⇒ f’(x) = ![]()
⇒ f’(x) = ![]()
∴ f’(x) = ![]()
Hence,
Derivative of f(x) = tan √x = ![]()
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