As we know that 1+cos 2x = 2sin2 x
As, π/2 < x < π
∴ sin x will be positive.
Let Z = 
⇒ Z = 
⇒ Z =
{ as we need to consider positive square root}
∵ sin x is positive
∴ Z = ![]()
We know that differentiation of sin x is cos x
Hence,
Z = cos x
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