The mean and standard deviation of a group of 100 observations were found to be 20 and 3 respectively. Later on, it was found that three observations were incorrect, which were recorded as 21, 21 and 18. Find the mean and standard deviation if the incorrect observations were omitted.
To Find: Find the correct mean and standard deviation.
Explanation: Here, n=100,![]()
X = ![]()

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So, Corrected ![]()
Corrected ![]()
Now, Standard variance
= 3
Since, Variance = ![]()
Variance = 9
X = ![]()
9 = ![]()
9 = ![]()
![]()
Corrected ![]()
Corrected ![]()
Correct mean = ![]()
Corrected Variance = ![]()
![]()
409.22-400
Corrected variance =9.22
Now, Corrected Standard Deviation = ![]()
![]()
Correct Deviation is 3.04
Hence, The correct Mean is 20 and Correct SD is 3.04
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