Find the mean and variance of frequency distribution given below:

Given, The data is given in table
To Find: Find the mean and, the variance of the frequency
Explanation: Here, the class interval is not continues frequency distribution, So we have to convert into continues frequency distribution by subtracting 0.5 from the lower limit and adding 0.5 to the upper limit then we get,

Now, N=16,
, ![]()
Mean ![]()

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Variance = 3.74
Hence, The variance is 3.74
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