Prove each of the following identities:
[CBSE 2007]
Consider L.H.S. = ![]()
= ![]()
= ![]()
= ![]()
Thus, prove.
Also, consider
= ![]()
= ![]()
= R.H.S.
Hence, proved.
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[CBSE 2006]
[CBSE 2007]
[CBSE 2008]