If cosec θ = 2x and cot θ = 2/x find the value of 2
.[CBSE 2010]
Given: 2x = cosec θ , and 2/x = cot θ
Consider 2(x2 – (1/ x2)) = ![]()
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= ![]()
= (1/2)(cosec2 θ – cot2 θ)
= 1/2 (∵ cosec2 x – cot2 x = 1)
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[CBSE 2010]