If sin θ = 1/2, write the value of (3 cot2 θ + 3). [CBSE 2009]
Give: sin θ = 1/2
Therefore cosec θ = 1/sin θ
= 2
Consider 3 cot2 θ + 3 = 3 (cot2 θ + 1)
= 3 cosec2 θ (∵ 1 + cot2 θ = cosec2 θ)
= 3 (2)2
= 3 × 4
= 12
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[CBSE 2010]