Q23 of 29 Page 8

Write the value of sec2 θ (1 + sin θ)(1 – sin θ). (CBSE 2009)

Consider sec2 θ (1 + sin θ)(1 – sin θ) = sec2 θ (1 – sin2 θ)

= sec2 θ cos2 θ


(∵ sin2 θ + cos2 θ = 1)


= 1

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