Q10 of 37 Page 14

For a certain distribution, mode and median were found to be 1000 and 1250 respectively. Find mean for this distribution using an empirical relation.[CBSE 2014]

Given: mode = 1000 and median = 1250

The empirical relationship between mean, median and mode is,


Mode = 3(Median) – 2(Mean)


⇒ 2(Mean) = 3(Median) – Mode


⇒ Mean = [3(Median) – Mode]/2


⇒ Mean = [3(1250) – 1000]/2


⇒ Mean = [3750 – 1000]/2 = 2750/2 = 1375


∴ mean = 1375

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cummulative frequency (cf)

100 - 200

11

11

200 - 300

12

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300 - 400

10

33

400 - 500

Q

46

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20

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7

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30

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Find the mode of the given data: [CBSE 2015]


Class interval

0 - 20

20 - 40

40 - 60

60 - 80

Frequency

15

6

18

10
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Compute the mean of the following data, using direct method: [CBSE 2005]


Class

0 - 100

100 - 200

200 - 300

300 - 400

400 - 500

Frequency

6

9

15

12

8