Compute the mean of the following data: [CBSE 2013]
Class |
1 - 3 |
3 - 5 |
5 - 7 |
7 - 9 |
Frequency |
12 |
22 |
27 |
19 |
For equal class intervals, we will solve by finding mid points of these classes using direct method.
CLASS |
MID - POINT(xi) |
FREQUENCY(fi) |
fixi |
1 - 3 |
2 |
12 |
24 |
3 - 5 |
4 |
22 |
88 |
5 - 7 |
6 |
27 |
162 |
7 - 9 |
8 |
19 |
152 |
TOTAL |
80 |
426 |
We have got
Σfi = 20 & Σfixi = 426
∵ mean is given by
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Thus, mean is 5.325
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