In a hospital, the ages of diabetic patients were recorded as follows. Find the median age.[CBSE 2014]
Age (in years) |
0 - 15 |
15 - 30 |
30 - 45 |
45 - 60 |
60 - 75 |
Number of patients |
5 |
20 |
40 |
50 |
25 |
To find median,
Assume Σfi = N = Sum of frequencies,
h = length of median class,
l = lower boundary of the median class,
f = frequency of median class
and Cf = cumulative frequency
Lets form a table.
AGE(years) |
NUMBER OF PATIENTS(fi) |
Cf |
0 - 15 |
5 |
5 |
15 - 30 |
20 |
5 + 20 = 25 |
30 - 45 |
40 |
25 + 40 = 65 |
45 - 60 |
50 |
65 + 50 = 115 |
60 - 75 |
25 |
115 + 25 = 140 |
TOTAL |
140 |
So, N = 140
⇒ N/2 = 140/2 = 70
The cumulative frequency just greater than (N/2 = ) 70 is 115, so the corresponding median class is 45 - 60 and accordingly we get Cf = 65(cumulative frequency before the median class).
Now, since median class is 45 - 60.
∴ l = 45, h = 15, f = 50, N/2 = 70 and Cf = 65
Median is given by,

⇒ ![]()
= 45 + 1.5
= 46.5
Thus, median age is 46.5 years.
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