On a multiple-choice examination with three possible answers (out of which only one is correct) for each of the five questions, what is the probability that a candidate would get four or more correct answers just by guessing?
Given: n = 5, p = P (correct answer) = 1/3
∴ q = 1 – p = 1- 1/3 = 2/3
We know that P (r) = nCr. qn-r. pr
∴ P (4 or more correct answers) = P (4) + P (5)
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