Using properties of determinants, prove the following:

Given; 
Taking x from C1, y from C2 and z from C3

C1→ C1 +C2 + C3

Taking
from C1

R2→ R2 – R1 and R3→ R3 – R1

Evaluating along C1
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= xyz + xy + yz +zx.
Hence Proved
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