Find the area of the region included between the parabola 4y = 3x2 and the line 3x - 2y + 12 = 0.
Given; The parabola 4y = 3x2 and
the line 3x - 2y + 12 = 0.

By solving the equations;
![]()
![]()
![]()
![]()
∴ x = 4,-2 and y = 12, 3
∴ Required Area ![]()

![]()
= 9 + 36 – 18 = 27 sq.units
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.


