Using properties of determinants, prove the following:

Given: 
Performing the operations R2→ R2 – 2R1 and R3→ R3 – 3R3, we get

Expanding along C1, we get
= 1 [3p – 2 – 3(-1 + p)]
= -2 + 3p + 3 – 3p
= 1 = RHS
Hence proved.
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