Q4 of 68 Page 27

In each of the following cases, find a and b.

Given:

To find: the value of a and b

Explanation: Now given the ordered pairs are equal, so corresponding elements will be equal, i.e.,

and a-2b = 6 + b

Now

⇒a = 0

Substituting the value of a in the equation (a-2b = 6 + b), we get

0-2b = 6 + b

⇒ -2b-b = 6

⇒ -3b = 6

⇒ b = -2

Hence the value of a and b are 0 and -2 respectively

If A = {x : x ∈ W, x < 2} B = {x : x ∈ N, 1 < x < 5} C = {3, 5} find

(i) A × (B ∩ C)

(ii) A × (B ∪ C)

In each of the following cases, find a and b.

(2a + b, a – b) = (8, 3)

Given A = {1, 2, 3, 4, 5}, S = {(x, y) : x ∈ A, y ∈ A}. Find the ordered pairs which satisfy the conditions given below:

x + y = 5

Given A = {1, 2, 3, 4, 5}, S = {(x, y) : x ∈ A, y ∈ A}. Find the ordered pairs which satisfy the conditions given below:

x + y < 5