Given A = {1, 2, 3, 4, 5}, S = {(x, y) : x ∈ A, y ∈ A}. Find the ordered pairs which satisfy the conditions given below:

x + y = 5

Given: A = {1, 2, 3, 4, 5}, S = {(x, y) : x ∈A, y ∈A}

To find: the ordered pairs which satisfy the conditions x + y = 5

Explanation: Given: A = {1, 2, 3, 4, 5}, S = {(x, y) : x ∈A, y ∈A}

We need to find the ordered pair such that x + y = 5, where x and y belongs to set A = {1, 2, 3, 4, 5}

1 + 1 = 2≠5

1 + 2 = 3≠5

1 + 3 = 4≠5

1 + 4 = 5, so one of the ordered pair is (1, 4)

1 + 5 = 6≠5

2 + 1 = 3≠5

2 + 2 = 4≠5

2 + 3 = 5, so one of the ordered pair is (2, 3)

2 + 4 = 6≠5

2 + 5 = 7≠5

3 + 1 = 4≠5

3 + 2 = 5, so one of the ordered pair is (3, 2)

3 + 3 = 6≠5

3 + 4 = 7≠5

3 + 5 = 8≠5

4 + 1 = 5, so one of the ordered pair is (4, 1)

4 + 2 = 6≠5

4 + 3 = 7≠5

4 + 4 = 8≠5

4 + 5 = 9≠5

5 + 1 = 6≠5

5 + 2 = 7≠5

5 + 3 = 8≠5

5 + 4 = 9≠5

5 + 5 = 10≠5

So, the set of ordered pairs satisfying x + y = 5 is {(1,4), (2,3), (3,2), (4,1)}.