Q12 of 68 Page 27

Let f and g be real functions defined by f (x) = 2x + 1 and g (x) = 4x – 7.

For what real numbers x, f (x) < g (x)?

Given: f and g be real functions defined by f(x) = 2x + 1 and g(x) = 4x-7


To find: For what real numbers x, f (x) < g (x)


Explanation: to satisfy the condition f(x)<g(x), we should have


i.e., 2x + 1<4x-7


⇒ 7 + 1<4x-2x


⇒ 8<2x


Or, 2x>8


⇒ x>4


Hence for x>4, f (x) > g (x)


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